def find_qq_number(name):
    qq_dict = {
        'xiaoyun': '88888',
        'xiaohong': '5555555',
        'xiaoteng': '11111',
        'xiaoyi': '12341234',
        'xiaoyang': '1212121'
    }
    if name in qq_dict:
        return qq_dict[name]
    else:
        return "Not Found"


while True:
    input_name = input("请输入大佬的姓名：")
    qq_number = find_qq_number(input_name)
    print(qq_number)

    choice = input("是否继续运行？(y/n) ")
    if choice.lower() != 'y':
        break
